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Speed of boat= 30.0 m/s Acceleration = -3.50 m/s2 Distance= 100 m Let 'v' be the final velocity We know that 2as = v² - u² -2 × 3.5 × 100 = v² - (30)² -700 = v² - 900 v² = 200 v = 10?2 (10× square root of 2) v = 14.14 ( square root of 2 is 1.414 ) Answer is : v = 14.14 or 10?2 is the velocity of the boat when it reaches the buoy Now, t = (v-u)÷a t = ( 14.14 - 30 ) ÷ (-3.5) t = 4.5 s Answer is : t = 4.5 s

Speed of boat= 30.0 m/s Acceleration = -3.50 m/s2 Distance= 100 m Let 'v' be the final velocity We know that 2as = v² - u² -2 × 3.5 × 100 = v² - (30)² -700 = v² - 900 v² = 200 v = 10?2 (10× square root of 2) v = 14.14 ( square root of 2 is 1.414 ) Answer is : v = 14.14 or 10?2 is the velocity of the boat when it reaches the buoy Now, t = (v-u)÷a t = ( 14.14 - 30 ) ÷ (-3.5) t = 4.5 s Answer is : t = 4.5 s