A speedboat moving at 30.0 m/s approaches a no-wake buoy marker 100 m ahead. The pilot slows the boat with a constant acceleration of -3.50 m/s2 by reducing the throttle. (a) How long does it take the boat to reach the buoy? What is the velocity of the bo

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    Speed of boat= 30.0 m/s Acceleration = -3.50 m/s2 Distance= 100 m

    Let 'v' be the final velocity

    We know that

    2as = v² - u²

    -2 × 3.5 × 100 = v² - (30)²

    -700 = v² - 900

    v² = 200

    v = 10?2 (10× square root of 2)

    v = 14.14 ( square root of 2 is 1.414 )

    Answer is :

    v = 14.14 or 10?2 is the velocity of the boat when it reaches the buoy

    Now,

    t = (v-u)÷a

    t = ( 14.14 - 30 ) ÷ (-3.5)

    t = 4.5 s

    Answer is : t = 4.5 s

    • 16 Jul 2019 @ 08:06


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